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Method 1 :
angle QPR = 104 + 107 – 180 = 31 (sum of angles on a str. line)
angle AQP = angle APQ = 104 – 31 = 73 degrees (isos. triangle)
angle CRP = angle CPR = 107 – 31 = 76 degrees (isos. triangle)
angle PQB = 180 – 73 = 107 (sum of angles on a str. line)
angle PRB = 180 – 76 = 104 (sum of angles on a str. line)
angle QBR = 360 – 104 – 107 – 31 = 118

Method 2 :
angle QPR = 104 + 107 – 180 = 31 (sum of angles on a str. line)
angle APQ = angle AQP = 104 – 31 = 73 degrees (isos. triangle)
angle PAQ = 180 – 2 x 73 = 34 (isos. triangle)
angle CPR = angle CRP = 107 – 31 = 76 degrees (isos. triangle)
angle PCR = 180 – 2 x 76 = 28 (isos. triangle)
angle QBR = 180 – 34 – 28 = 118

Ans : 118 degrees.

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This is a Geometry question.

104 and 107 are overlapping.

RPC = 180 – 104 = 76

QPA = 180 – 107 = 73

PCR = 180 – 76 – 76 =28

PAB = 180 – 73 – 73 = 34

ABC = 180 – 28 – 34 =  118

 

 

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