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# Question

# Answer

(a)

In Figure A, draw a line from the top left corner from Figure A to its bottom left which will look like the one in Figure B. Shift the two segments to fill the overlapping semicircles tyo obtain the shaded triangle in Figure B.

(b)* shaded* area of Figure A = shaded area of Figure B = (1/2) x 14 x 14 = 98

or

(1/4) x (22/7) x 7 x 7 = 38.5

(1/2) x 7 x 7 = 24.5

(1/2) x (22/7) x 7 x 7 + [(7 x 7) – (1/4) x (22/7) x 7 x 7] x 2 = 98

(c)

perimeter of figure A = (22/7) x 14 + 2 x 14 = 72

Ans : (a) as above; (b) 98 sq cm; (c) 72 cm.

This is a Geometry question.

a)

Draw a straight line from top right corner to the bottom left corner in figure A.

Cut the two segments and past them in the centre unshaded area.

b)

Area = 1/2 × 14 × 14 = 98

c)

Perimeter = 1 circle

= pi × 14 × 2

= 28 × 22/7

= 88

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