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Method 1 :
(a)
Scenario 1 : If Nelly used 119 cm of her cloth, she would have left thrice the length of cloth Irena had,
Nelly : 119 + (1 unit + 47) + (1 unit + 47) + (1 unit + 47) = 3 units + 260
Irena : (1 unit + 47)

Scenario 2 : If Irena used 47 cm of her cloth, Nelly would have 7 times the length of cloth Irena had left,
7 units = 3 units + 260

1 unit = 260/(7 – 3) = 65
3 units + 260 = 3 x 65 + 260 = 455

(b)
1 unit + 47 = 65 + 47 = 112

 

Method 2 :
(a)
Scenario 1 : If Nelly used 119 cm of her cloth, she would have left thrice the length of cloth Irena had,
Nelly – 119 ——-> 3 x Irena
7 x Nelly – 833 ——-> 21 x Irena

Scenario 2 : If Irena used 47 cm of her cloth, Nelly would have 7 times the length of cloth Irena had left,
(Irena – 47) x 7 = 7 x Irena – 329 ——-> Nelly
21 x Irena – 987 ——-> 3 x Nelly
21 x Irena ——-> 3 x Nelly + 987
7 x Nelly – 833 ——-> 3 x Nelly + 987
Nelly ——-> (987 + 833)/(7 – 3) = 455

(b)
455 – 119 = 336 ——-> 3 x Irena
Irena ——-> 336/3 = 112

Ans : (a) 455 cm; (b) 112 cm

1 Reply 0 Likes

Hi,

Can you help to simplify the methods or with a model? I still can’t figure out your working so cant explain it to my DD. 

Thank.you 😊

1 Reply 0 Likes

Sure; another method, Method 1, has been added to aid you. Don’t mention.

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Thank you very much !!

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You are most welcome!

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This is  a After Before After Ratio question.

   After    Transfer  Before  Transfer After    
Nelly  3u + 119 3u + 119   3u +119
Irene   1u   1u – 47 1u – 47

(3u + 119)/ 7  = (1u – 47) / 1

3u + 119 = 7u – 329

119 + 329 = 7u -3u

4u = 448

b)

1u = 448 ÷ 4 = 112 cm

a)

3u = 112 × 3 = 336

336 + 119 = 455 cm

 

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