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Question

Mandy drove from Town B towards Town C at 9.50am. Half an hour later, Nancy left Town C for Town B. Both of them reached their respective destinations at 10.50am. If Nancy travelled at 20km/h faster than Mandy, find the speed of Nancy.

 

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Answer

Let Mandy speed be 1u

      1u x 1 = (1u+20) x 0.5
1u – 0.5u = 10
       0.5 u = 10
            1u = 10 x 2 = 20
20 + 20 = 40km/h as the answer

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This is a Distance Speed Time question.

   Time     Speed     Distance 
Mandy     1 1u 1u
Nancy 0.5 1u  +20 0.5u + 10

1u = 0.5u + 10

1u – 0.5u = 10

0.5u = 10

1u = 10 ÷0.5 = 20

20 + 20 = 40 km/h

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