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Question

hi,

 

Along a road, spot X and spot Y are 1150 m apart. Ann walks along the road from X to Y at 2/3 m/s. Yohan walks along the same road from Y to X at 1 1/4 m/s. Both start walking at the same time.

 

a) How many minutes later will they meet?

b)How far is their meeting point away from X?

Answer

Another way to think about this are two of these conditions

1. The distance travelled by Ann and Yohan adds up to 1150m

2. The time taken by both of them is the same

Hence this equation

1150 = (2/3.t) + (5/4.t) 

        = (2/3 + 5/4). t = 23/12.t

t =  1150 / (23/12) = 600 sec or 10 minutes #. Answer for a) 

B. 

2/3 x 600 = 400 m # answer for b) 

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Can use ratio. 

Ann speed 2/3 => 8/12 m/s

Yohan speed, 5/4 => 15/12 m/s

Ann : Yohan : total => 8 : 15 : 23

Since speed is proportional to distance travelled, the ratio for distance is also 8 : 15 : 23

Ann traveled, 8/23 x 1150 = 400m. Also distance from X. Answe for b)

Time taken = 400/ (2/3) = 600 secs or 10 minutes. Answer for a) 

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What is the speed of Ann?

Yohan speed is 1m/s or 1 m/s faster than Ann?

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Hi Pek Mao, thanks to point it out for my mistake. i had updated the Q. thanks.

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