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Can see that the pattern repeats after 4 numbers, 4012.

Just divide the position by 4. The remainder will tell which number it is.

A) Remainder of 626/4 is 2.  Then it is the 2nd number of 4012, which is 0 #

B) The sum for each set is 4 + 0 + 1 + 2 = 7

The quotient for 627/4 is 156

Therefore there are 156 complete sets of 7 and the sum of the remainder of 3 numbers is 4 + 0 + 1 =5.

Sum of the 1st 627 numbers is 156 x 7 + 5 = 1097#

0 Replies 1 Like ✔Accepted Answer

each set has numbers 4, 0, 1, 2 

4 numbers per set

626/ 4 and find the remainder = 2, 626th number is 0 (2nd number in the set) 

sum of each set = 7
fine the number of full sets + sum of remaining numbers

 

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