# Question

Q1:

Kate reads 60 pages of a book on the first day. This is 20% more than the number of pages she reads on the second day. Given that she reads 1/6 of the book on the second day, find the number of pages in the book.

Q2:

A vendor sells apples, pears and oranges. He has 120 oranges. Given that he has 20% more apples than oranges and 40% fewer oranges than pears, find the total number of fruits he has.

pls kindly help. thanks.

Q1 is a Part whole question.

1. Day1  120u = 60

1u = 60 ÷ 120 = 0.5

Day 2   100u = 100 × 0.5 = 50

2. 1a = 50

6a = 50 × 6 = 300 pages

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Q1,

120% ——-> 60
100% ——-> 50 (second day)
50 x 6 = 300
Ans : 300 pages.

Q2.
100% ——-> 120
120% ——-> 144 (apples)
100% – 40% = 60% ——-> 120
100% ——-> 200 (pears)
120 + 144 + 200 = 464

Ans : 464 fruits.

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For question 2. The question requires you to understand which item is the reference point. For reference point, I mean the one we will treat it as the 100%. Let’s go thru the two statments to determine which item is the reference point.

“he has 20% more apples than oranges”
“than oranges” means that the oranges are the reference point.
100% => 120
10% => 12
120% => 12 X 12 = 144 apples

“40% fewer oranges than pears”
“than pears” means pears are the reference point, therefore it is the 100%. Which means orange are 60% of pear.
60% => 120
10% => 120/6 = 20
100% => 20 X 10 =200 pears.

Total fruits = 200 + 144 + 120 = 464 fruits ###

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Q2 is a Part Whole question.

1. Apple is 20% more than orange. So apple = 120u

2. Pear is 40% than  orange. So pear = 140u

3. Orange 100u.

4. Total 360u.

100u = 120

1u = 1.2

360u = 1.2 × 360 = 432 fruits

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