I have calculated that the rise in water for Tank X is 4 cm/min. And drop in height for Tank Y to be 2.8 cm/min.
It is flow rate divide by the base area,
- Rise in cm rate for X = 2800/700 = 4cm/min
- Drop in cm rate for Y = 2800/1000 = 2.8 cm/min
“t” is the time in minutes for the height of both tanks to be equal . The height is expressed as 4t for tank X and 34 -2.8t for tank Y.
4t = 34 – 2.8t
6.8t = 34
t = 5 mins##