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This is a Before After question.

1. Total ball 160. Total marble 120.

2. Basket A. Ball 40u. Marble 60u.

3. Use compliment method to find Basket B.

    Ball    Marble    Total  
Basket  A 40u  60u   
Basket B  160 – 40u  120 – 60u   
Total 160 120  

(160 – 40u) / 70  = (120 – 60u) / 30        ÷ 10

480 – 120u    = 840  – 420u

420u – 120u = 840 – 480

300u = 360

1u = 360 ÷ 300 = 1.2

40u = 1.2 × 40 = 48

60u = 1.2 × 60 = 72

170 – 48 – 72 = 50  😊

 

Note

You may this method even there is a mixture of transfer, eg marble from A to B, and ball from B to A.

Similar problem, male and female in the  hall and field, cakes and buns in tray A and tray B.

 

 

 

 

 

 

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Remember constant total of Balls and constant total for marbles.
Total balls = 160
Total marble = 120

Finally
Basket A contains balls : marbles => 40u : 60u
Basket B contains balls : marbles => 70p : 30p

60u + 30p = 120 …….(1)

40u + 70p = 160
60u + 105p = 240 ……(2)

(2) – (1)
75p = 120
p = 1.6

Finally Basket B contain
Balls = 70p = 112
Marbles = 30p = 48

Balls transferred = 112 – 90 = 22 balls
Marbles transferred = 48 – 20 = 28 marbles
Altogether = 22 + 28 = 50 ###

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