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The question stated the quarter circle is enclosed in the square, and primary school are not taught pythagoras theorem.

Quarter circle = 2xPi X10 /4 = 5π

a)Perimeter = 18.87 + 6 + 5π = 40.57 cm ##

b)
Area of Quarter Circle = 1/4 X 3.14 X 10 X 10 = 78.5 cm2

Area of Unshaded A = Area of square – Area of quarter circle = 10 X 10 = 78.5 = 21.5 cm2

Area of triangle PUQ = 1/2 X 16 X 10 = 80 cm2

Area of shaded region = 80 – 21.5 = 58.5 cm2 ###

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