Find Tuition/Enrichment Centres

AskQ logo

STUCK ON HOMEWORK?

ASK FOR HELP FROM OUR KIASUPARENTS.COM COMMUNITY!

Question

The distance between Town P and Town Q was 216km. At 0710, Timothy left Town P for Town Q. At 0830, Steven left Town Q for Town P. Both did not change their speed throughout. The ratio of Timothy’s speed to Steven’s speed was 4:3. When they met each other, their distance from Town P was twice their distance from Town Q. Fin Timothy’ speed in km/h.

 

 

Answer

Method 1 :
Town P ————-——-———— 216 km ————–—————- Town Q
0710, Timothy ——-> …………………….…….….……………..…………..… <——- 08 30, Steven

0710 ——- 80 min ——- 0830
216/3 = 72 (distance Steven travelled)
216 – 72 = 144 (distance Timothy travelled)
Timothy’s speed : Steven’s speed
4 : 3

(72/3) x 4 = 96 (distance Timothy travelled from 0830 till meeting Steven)
144 – 96 = 48 (distance Timothy travelled from 0710 to 0830)
48/(80/60) = 64

Method 2 :
Town P ————-——-———— 216 km ————–—————- Town Q
0710, Timothy ——-> ………………….…………..…………..…..………..… <——- 08 30, Steven

0710 ——- 80 min ——- 0830
total distance Steven travelled = 3u = 216/3 = 72
total distance Timothy travelled = 6u = 216 – 72 = 144
Timothy’s speed : Steven’s speed
4 : 3

distance travelled by Timothy from 0710 to 0830 = 144/(6 – 4) x 2 = 48
48/(80/60) = 64

Ans : 64 km/h.

0 Replies 0 Likes
Find Tuition/Enrichment Centres