 # Question Hi,

Can someone help on this question again ? There’s answer on the answer sheet but we do not understand how to solve it.

Thank you ~

Number of pens in box A = 1.25 units
Number of pens in box B = 1 unit
Number of pens in box C = 1.25 units + 45

0.4 x (2.25 units + 45) = 0.9 unit + 18 = 288
1 unit = 300
40% x 1.25 units = 150
(150 + 288)/73 = 6

Ans : 6 pens.

0 Replies 0 Likes

is it

1packet= 6pens?

Can explain how did u solve it ?

Thanks

Hi, Sorry for the late reply. Here is how I got it.

BoxB= 100%= 1u

BoxA= BoxB + 25%= 1u + 0.25u= 1.25u

BoxC= BoxA + 45 pens= 1.25u +45pens

73packets = 40%BoxA + 40%BoxB +40%BoxC = 0.4BoxA +0.4BoxB +0.4BoxC

288pens = 40%BoxB + 40%BoxC = 0.4 (1u) + 0.4(1.25u+45pens)= 0.4u + 0.5u + 18pens

288pens =0.9u +18pens

288pens -18pens =0.9u

270 pens= 0.9u

1u= 300 pens

Therefore;

BoxB = 300pens

BoxA = 1.25u= 375pens

BoxC= BoxA + 45 pens = 420pens

If ,

73packets = 0.4BoxA + 0.4BoxB + 0.4BoxC

73packets = 150 + 120 + 168 =438 pens

So,

1packet = 438/73 = 6pens

0 Replies 0 Likes

This question is erroneous as the answer is coming out as fraction

0 Replies 0 Likes