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Question

Hi,

Can someone help on Ans (b)?

We got answer 22.5 but not sure is it correct. Thanks 

Answer

As OPQR is a rhombus, RQ//SP

As RQ//SP, ∠QRS + ∠RSP = 180º

As OR = OS = OT, inside triangle ORS, ∠ORS = ∠RSO = ∠SOR = 60º

Inside ORT, ∠ORT = ∠OTR = (180º – ∠TOR)÷2 = (180 – 90 – 60)÷2 = 15º

∠RTS = ∠OTS – ∠OTR = 45º -15º = 30º

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Thank you very much!

We understand now.

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