please help to solve the 2 questions. thank you.

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# Question

# Answer

THW

The triangle ABC is one quarter of a square of side 6 cm.

Area of triangle ABC = 1/4 × 6 × 6 = 9

Let AB = BC = R, the radius of the circle.

Then Area of triangle ABC = 1/2 × R × R = 1/2 R² = 9

R² = 18

Area of 3/4 of the circle = 3/4 × π × R² = 3/4 × 3.14 × 18 = 42.39

Area of the figure = 9 + 42.39 = 51.39 cm²

THW

The triangle ABC is one quarter of a square of side 6 cm.

Area of triangle ABC = 1/4 × 6 × 6 = 9

Let AB = BC = R, the radius of the circle.

Then Area of triangle ABC = 1/2 × R × R = 1/2 R² = 9

R² = 18

Area of 3/4 of the circle = 3/4 × π × R² = 3/4 × 3.14 × 18 = 42.39

Area of the figure = 9 + 42.39 = 51.39 cm²

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