Box A contains 50-cent coins and Box B contains 20-cent coins. Box B has twice as many coins as Box A. The amount of money in Box A is $1.40 more than the amount of money in Box B.
(a) How many 20-cent coins are there?
(b) How much money is in both boxes altogether?
Since Box-B is twice as much as Box-A.
In a set there is two 20-cent and one 50-cent.
The difference is 10-cent for a set.
14 set of two 20-cent and one 50-cent will give the difference of $1.40.
14 * 2 = 28 (Because 14 set of two 20-cent)
Setp
a) $0.20 * 2 = $0.40
$0.50 – $0.40 = $0.10
$1.40 / $0.10 = 14
14 * 2 = 28
b) 28 * $0.20 = $5.60
14 * $0.50 = $7 or $5.60 + $1.40 = $7
$5.60 + $7 = $12.60
tq!
