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   3x– 5x+ 4

=x2(3x-5) + 4

=x2(3x+6-6-5) +4

=x2[3(x+2)-11] +4

=3x2(x+2)-11x2 +4

=3x2(x+2)-(11x2 +22-22)+4

=3x2(x+2)-11(x2 +2)+22+4

=3x2(x+2)-11(x2 +2)+26

=(x2 +2)(3x2-11)+26

Hence, the remainder is 26.

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