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It would be easier if the pens are considered as 1 unit, ignoring the colors. 

Initially,

Box A = 6U  => Red

Box B = 3U  => Blue 

First transfer

Box A = 3U (R) + 2U (B)

Box B  = 1U(B) + 3U (R)

Second transfer  8 blue pens and 5 red pens are transferred from A  to B. 

13 pens are transferred from A to B. 

Box A has 5U

Box B has 4U 

Since they both will be equal after 13 pens are transferred from A to B, 

5U = 4U + 26

1U = 26. 

Total blue pens = 3U = 26 x 3 = 78

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