# Question

Hi Shifus, kindly help with this question please. Answer is 140 but I’m stuck with the method. Thank you in advance.

Source: Springdale Primary

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Thank you. I had gotten 20 too. But the answer showed 140 hence I was wondering what I could have done wrong. Your reply reaffirms my answer is correct. Basically it’s unchanged difference between them. Thank you for your help. 🙏

(\$140/5) x 3 = \$84 (money Aaron had at first)

84 + 12 = 96

140 + 12 = 152

96 : 152

12 : 19 (\$140 is thus incorrect as the ratio could not be reduced to 3 : 4.)

Hi altp10, you are most welcome. Yes, your answer is indeed correct. Also, I believe that most if not all would agree that coaching students in checking their answers is essential too.

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This is a question, in which all the entities in a ratio change.

Between start and end, there is a change in the amount of money that Bala and Aaron hold.

 Aaron Bala Start 3u 5u + 12\$ +12\$ End 3p 4p

Cross-multiply to make the parts same, the modified table will be

 Aaron Bala Start 12U 15U +48\$ +36\$ End 12p 12p

since the parts are the same,

12U + 48 = 15U + 36

3U = 12

1U = 4\$

Money that Bala had at first was 5U = 5 x 4\$ = 20\$

Verify

Initially, Bala = 20\$, Aaron = 12\$

Adding 12\$, Bala = 32\$, Aaron = 24\$

24 : 32  = 6:8 = 3:4