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The meeting point is 2 times from P than Q. 

Given the total distance of 216 km, meeting point must be 144 km from P and 72 km from Q. 

3units = 216, 1 unit = 72km. 

Distance from P = 2U = 2 x 72 = 144km. 

Distance from Q = 1U = 1 x 72 = 72km. 

This difference in distance is achieved due to two factors.

  1. Timothy has started early (time difference).
  2. Timothy is driving faster than Steven ( speed difference, ratio 4:3)

The difference due to speed must be accommodated first. The ratio of speed is 4:3, so if Steven has traveled 72 km, then Timothy must travel 

(72  / 3) x 4 = 24 x 4 =  96 km. 

But Timothy has traveled 144 km, i.e 144 – 96 = 48 km in excess of Steven. This is due to the fact that Timothy started early, 80 mins ahead of  Steven. (8.30 – 7.10 = 80 mins)

 so Timothy has traveled 48 km in 80 mins. So, his speed is 

(48/80) x 60 = 36 km/hr. 

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