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# Question

# Answer

The meeting point is 2 times from P than Q.

Given the total distance of 216 km, meeting point must be 144 km from P and 72 km from Q.

3units = 216, 1 unit = 72km.

Distance from P = 2U = 2 x 72 = 144km.

Distance from Q = 1U = 1 x 72 = 72km.

This difference in distance is achieved due to two factors.

- Timothy has started early (time difference).
- Timothy is driving faster than Steven ( speed difference, ratio 4:3)

The difference due to speed must be accommodated first. The ratio of speed is 4:3, so if Steven has traveled 72 km, then Timothy must travel

(72 / 3) x 4 = 24 x 4 = 96 km.

But Timothy has traveled 144 km, i.e 144 – 96 = 48 km in excess of Steven. This is due to the fact that Timothy started early, 80 mins ahead of Steven. (8.30 – 7.10 = 80 mins)

so Timothy has traveled 48 km in 80 mins. So, his speed is

(48/80) x 60 = **36 km/hr.**

The meeting point is 2 times from P than Q.

Given the total distance of 216 km, meeting point must be 144 km from P and 72 km from Q.

3units = 216, 1 unit = 72km.

Distance from P = 2U = 2 x 72 = 144km.

Distance from Q = 1U = 1 x 72 = 72km.

This difference in distance is achieved due to two factors.

- Timothy has started early (time difference).
- Timothy is driving faster than Steven ( speed difference, ratio 4:3)

The difference due to speed must be accommodated first. The ratio of speed is 4:3, so if Steven has traveled 72 km, then Timothy must travel

(72 / 3) x 4 = 24 x 4 = 96 km.

But Timothy has traveled 144 km, i.e 144 – 96 = 48 km in excess of Steven. This is due to the fact that Timothy started early, 80 mins ahead of Steven. (8.30 – 7.10 = 80 mins)

so Timothy has traveled 48 km in 80 mins. So, his speed is

(48/80) x 60 = **36 km/hr.**

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