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Using Pythagoras’ Theorem,
PQ = √(25²-7²) = 24

Since (P’O)² + (OQ’)² = 25²,
(24-x)² + (2x+7)² = 25²
576 – 48x + x² + 4x² + 28x + 49 = 625
5x² – 20x = 0
5x(x – 4) = 0
x = 0, 4

Since x > 0, x = 4

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Thank you so much!

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