Find Tuition/Enrichment Centres

AskQ logo

STUCK ON HOMEWORK?

ASK FOR HELP FROM OUR KIASUPARENTS.COM COMMUNITY!

Question

Answer

By drawing another line from the bottom left corner of square to its top right, the shaded area is divided into 2 parts : upper and lower.
area of upper part: = (1/4) x (22/7) x 28/2 x 28/2) – (1/2) x (28/2) x (28/2) = 154 – 98 = 56
area of lower part = [(1/4) x (22/7) x 28 x 28 – (1/2) x 28 x 28]/2 = (616 – 392)/2 = 112
56 + 112 = 168

Ans : 168 sq m.

0 Replies 0 Likes

With reference to picture attached:

You can see the shaded area is divided into two parts by the red line.

Area of top shaded part = (Area of semi-circle DOC – Area of triangle DOC) ÷ 2
= [(1/2 x 22/7 x 14 x 14) – (1/2 x 28 x 14)] ÷ 2
= (308 – 196) ÷ 2
= 112 ÷ 2
= 56 m2

Area of bottom shaded part = (Area of quadrant ADB – Area of triangle ADB) ÷ 2
= [(1/4 x 22/7 x 28 x 28) – (1/2 x 28 x 28)] ÷ 2
= (616 – 392) ÷ 2
= 224 ÷ 2
= 112 m2

Area of whole shaded part → 56 + 112 = 168 m2

0 Replies 1 Like

Split shaded area into 2 parts by drawing the line from top right corner to bottom left corner of square

To find the lower part:(area of quadrant – area of triangle which is half square)÷2

To find the upper part:(area of semi-circle-area of triangle which is a quarter square)÷2

 

0 Replies 1 Like
Find Tuition/Enrichment Centres