Anyone know to solve this

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# Question

# Answer

**With reference to picture attached:**

You can see the shaded area is divided into two parts by the red line.

Area of top shaded part = (Area of semi-circle DOC – Area of triangle DOC) ÷ 2

= [(1/2 x 22/7 x 14 x 14) – (1/2 x 28 x 14)] ÷ 2

= (308 – 196) ÷ 2

= 112 ÷ 2

= 56 m^{2}

Area of bottom shaded part = (Area of quadrant ADB – Area of triangle ADB) ÷ 2

= [(1/4 x 22/7 x 28 x 28) – (1/2 x 28 x 28)] ÷ 2

= (616 – 392) ÷ 2

= 224 ÷ 2

= 112 m^{2}

Area of whole shaded part → 56 + 112 = **168 m ^{2}**

**With reference to picture attached:**

You can see the shaded area is divided into two parts by the red line.

Area of top shaded part = (Area of semi-circle DOC – Area of triangle DOC) ÷ 2

= [(1/2 x 22/7 x 14 x 14) – (1/2 x 28 x 14)] ÷ 2

= (308 – 196) ÷ 2

= 112 ÷ 2

= 56 m^{2}

Area of bottom shaded part = (Area of quadrant ADB – Area of triangle ADB) ÷ 2

= [(1/4 x 22/7 x 28 x 28) – (1/2 x 28 x 28)] ÷ 2

= (616 – 392) ÷ 2

= 224 ÷ 2

= 112 m^{2}

Area of whole shaded part → 56 + 112 = **168 m ^{2}**

Split shaded area into 2 parts by drawing the line from top right corner to bottom left corner of square

To find the lower part:(area of quadrant – area of triangle which is half square)÷2

To find the upper part:(area of semi-circle-area of triangle which is a quarter square)÷2

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