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Hello 🙂

we have :

2352=2a*3b*7c
So we have:

1176=a*3b*7c .         (2352/2=1176, we can do that according to the multiplication and division rules)

Then:

392=a*b*7c

we have then:

56=a*b*c

We need now to use prime factorization:
we know that 56=7*8
                              =7*2*4

So we can, for example, say that:

a=7; b=2; c=4

Let’s check our results:
2*7*3*2*4*7=14*6*28= 84*28=23532

Our results are good
Hope it will help 🙂

 

 

0 Replies 1 Like ✔Accepted Answer

2352 = 2a x 3b x 7c

2352 = 2 x 1176
= 2 x 2 x 588
= 2 x 2 x 2 x 294
= 2 x 2 x 2 x 2 x 147
= 2 x 2 x 2 x 2 x 3 x 49
= 2 x 2 x 2 x 2 x 3 x 7 x 7

From here, it should be easy to tell what the values of a, b, and c are:

2 x a = 2 x 2 x 2 x 2
a = 2 x 2 x 2
= 8

3 x b = 3
b = 1

7 x c = 7 x 7
c = 7


Check:

2(8) x 3(1) x 7(7) = 16 x 3 x 49
= 2352

0 Replies 1 Like
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