Find Tuition/Enrichment Centres

AskQ logo

STUCK ON HOMEWORK?

ASK FOR HELP FROM OUR KIASUPARENTS.COM COMMUNITY!

Question

Answer

a) Since ABGF is a rhombus, △ABF and △BGF are congruent and isosceles triangles

AFB = ABF = BFG = FBG = 27°
∠DBG = 180° – ABF – FBG – CBD
= 180° – 27° – 27° – 25°
= 101°

b) ∠CBD = ∠BDG = 25°
BDE = BDG + GDE

= 25° + 83°
= 108°

Since BD ∥ FE,
BDE + DEF = 180°
108° + DEF = 180°
DEF = 180° – 108°
= 72°

0 Replies 0 Likes
Find Tuition/Enrichment Centres