
Can you please help with this question?
Can you please help with this question?
a) As BCEF is a rhombus, this means that all of its sides are equal. ∴ △CBF = △CEF
b) As BCEF is a rhombus, BC = BF. ∴△CBF and △CEF are isosceles △s
∠BCF = ∠ECF = ∠EFC = 51°
∠FEC = 180° – ∠ECF – ∠EFC
= 180° – 51° – 51°
= 78°
c) ∠BCD = 360° – 51° – 51° – 147°
= 111°
∠CDA = 180° – ∠BCD (Angles between parallel lines)
= 180° – 111°
= 69°
∠BDC = ∠CDA – ∠BDA
= 69° – 32°
= 37°