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Let x be the number of stickers Charles has.

So Benny has x+80 stickers, and Dinesh has (9/4)*x stickers

During the game, Benny lost 1/4 of his stickers, so he is left with (3/4)x + 60, and Dinesh gets the same amount so Dinesh has (10/4)x + 20 stickers. 

In the next game, Charles wins 3/5 of Dinesh’s stickers, which is 3/5 * [(10/4) * x + 20]= (3/2)* x + 12

So Charles now has x + (3/2)x  + 12 = (5/2)x + 12 stickers, while Dinesh is left with (2/5)*[(10/4)x+20] = x + 8 stickers

So (5/2)x + 12 = 148 + (x + 8)

(3/2)x = 144

x = 144 * 2/3 = 96

Dinesh would have 96 + 8 = 104 stickers.

 

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