
Can someone please help with this question thank you for helping 🙏 in advance
Can someone please help with this question thank you for helping 🙏 in advance
AEFB is a trapezium with AB parallel to BF.
Angle BFE= 180° – 70° = 110° (interior angles / angles between parallel lines)
Angle EFD = Angle DFC, so Angle EFD = (180° – 70°) ÷ 2 = 35°
Angle EDF = Angle FDC, so Angle EDF = 180° ÷ 2 = 90°
Angle FED = 180° – 35° – 90° = 55°
Angle AEF = 180° – 55° = 125°
Hope you understand and all the best for your PSLE!
The question asked for ∠AEF, so you still need one more step (180º – 55º) to get 125º for the answer.
Oh yes! Thank you! I edited it accordingly