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Question

Can someone please help with this question thank you for helping 🙏 in advance

Answer

AEFB is a trapezium with AB parallel to BF.

Angle BFE= 180° – 70° = 110° (interior angles / angles between parallel lines)

Angle EFD = Angle DFC, so Angle EFD = (180° – 70°) ÷ 2 = 35°

Angle EDF = Angle FDC, so Angle EDF = 180° ÷ 2 = 90°

Angle FED = 180° – 35° – 90° = 55°

Angle AEF = 180° – 55° = 125°

Hope you understand and all the best for your PSLE!

1 Reply 1 Like

The question asked for ∠AEF, so you still need one more step (180º – 55º) to get 125º for the answer.

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Oh yes! Thank you! I edited it accordingly

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