
Hi…can anyone assist me for question number 2 and 3. Thanks advance..
Hi…can anyone assist me for question number 2 and 3. Thanks advance..
That’s for Question Three. Hope you understand!
QUESTION TWO
20-cent coins, before = 40u
20-cent coins, after = 20p
50-cent coins (unchanged) = 100u – 40u = 60u and 100p – 20p = 80p
60u = 80p
3u = 4p
So, if you convert p into u,
20-cent coins, after = (20p ÷ 4p) x 3u = 15u
So, 20-cent coins, removed is 40u – 15u = 25u
Fraction of 20-cent coins removed is 25/40 = 5/8 (simplified)
Hope you understand and all the best for your exams! :))