
Can help to show the solution on how to arrived that answer. Thanks a lot
Source: 2020 prelim
Can help to show the solution on how to arrived that answer. Thanks a lot
Source: 2020 prelim
Could it be the multiplier is set to be 1 (different from the usual 3 though), so
LCL = 12 – 1 × [0.3/√8] ≈ 12 – 0.11 =11.89
UCL = 12 + 1 × [0.3/√8] ≈ 12 + 0.11 =12.11
Please do let me know the teacher’s explanation. Thanks!