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sushi88
I did (b) without attempting (a) so here’s my solution.
___1____ – ___1_____ – __________4x___________ = 0
2(3x-2y) 2(3x+2y) – (3x-2y)(3x+2y)
_____ (3x +2y)_-_(3x-2y)__+_2(4x)_____ = 0
2(3x-2y)(3x+2y)
So the numerator, 3x-3x +2y +2y +8x = 0
4y = -8x
y/x = -8/4 = -2
If to do (a),
____4(y+2x)_______ = _____ 2(y+2x)______ (a single fraction)
2(3x-2y)(3x+2y) (3x-2y)(3x+2y)
then
(b) 2y+4x = 0
2y= -4x
y/x = -2
Adwin