Find Tuition/Enrichment Centres

AskQ logo

STUCK ON HOMEWORK?

ASK FOR HELP FROM OUR KIASUPARENTS.COM COMMUNITY!

Question

Answer

I did (b) without attempting (a) so here’s my solution.

 

___1____   –     ___1_____  –     __________4x___________      = 0

   2(3x-2y)              2(3x+2y)                          – (3x-2y)(3x+2y)

 

_____ (3x +2y)_-_(3x-2y)__+_2(4x)_____   = 0

                        2(3x-2y)(3x+2y)

So the numerator,  3x-3x +2y +2y +8x = 0

                                                                 4y = -8x

                                                               y/x = -8/4 = -2

 

If to do (a),

____4(y+2x)_______    =       _____ 2(y+2x)______    (a single fraction)

  2(3x-2y)(3x+2y)                          (3x-2y)(3x+2y)

 

then

(b)   2y+4x = 0

2y= -4x

y/x = -2

 

0 Replies 1 Like
0 Replies 1 Like
Find Tuition/Enrichment Centres