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Answer



Now
Janet -> 15
Mother -> 15 + 22 = 37
After x year
Janet -> 15 + x
Mother -> 37 + x
Given: Mother is twice as old as Janet
37 + x = 2(15 + x)
37 + x = 30 + 2x
x = 37 – 30 = 7
Mother will be twice as old as Janet after 7 years