
please do help 😼
please do help 😼
(a) Pretty straightforward, just divide the whole length (240) by the shorter side of the tile (y-5)
(b) No. of tiles in top row = 240 / (y – 5)
Thus, no. of tiles in top and bottom row = 2 [ 240 / (y – 5) ]
No. of tiles in left column = 160 / y
Thus, no. of tiles in left and right column = 2 [ 160 / y ]
One must realise that by adding up both terms, the tiles in the corners are double-counted, so they actually add up to 44 + 4 = 48. From here, we can formulate an equation in terms of y.
2 [ 160 / y ] + 2 [ 240 / (y – 5) ] = 48
Simplifying, we have:
20 / y + 30 / (y – 5) = 3
20 (y – 5) + 30 y = 3 (y) (y – 5)
20 y – 100 + 30 y = 3 y^2 – 15 y
3 y^2 -65 y + 100 = 0//
(c) By using whichever method you’re comfortable with:
Method 1:
 3 y | -5 | – 5y |
y | -20 | – 60y |
3 y ^ 2 | Â + 100 | – 65 y |
Method 2:
Apply quadratic equation, a = 3, b = -65, c = 100
You’ll end up with y = 5/3 (rej since y > 5) or y = 20. Thus the shorter side will be 20 – 5 = 15.
thanks  xxÂ