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Let ∠ACD be y degrees.
∠BCD is also y degrees.
By virtue of isosceles triangle ABC, ∠DBC = 2 y degrees
By virtue of isosceles triangle DBC, ∠CDB = 2 y degrees
Sum of angles in triangle DBC = 5 y degrees
Hence, 5 y = 180
y = 36
∠ADC = (180 – 2 y) degrees (Sum of ∠s in a straight line ADB)
= 180 – 2 (36)
= 108 degrees//